WebKul

## Sollicitatievraag

Sollicitatiegesprek voor de functie Python/Django Developer

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# # n=3 * * * @ * @ * @ * * * #n=5 * * * @ * * * @ * * * @ * * * @ * * * @ * * * somewhat similar to these !

## Antwoorden op sollicitatievragen

5 antwoorden

2

I was only able to do this : * * * @ * * * @ * * @ * @

Anoniem op

1

Please elaborate your question.. How question pattern looks like. It's seems in single line and you printed in multiple lines... thank-you

Anoniem op

1

n = int(input("num")) print("* " ) print("* ", end="") print("* ", end="") print("@ ", end="") print("\n") for i in range(n-2, 0, -1): m = n-1-i for j in range(i): print("* " , end="") print("@ ", end="") for k in range(m): print("* ",end="") print("\n") print(" ", end="") print(" ", end="") print("@ ", end="") print("* ", end="") print("* ") for m in range(5): if m<4: print(" ", end="") else: print("* ")

Deepak op

0

how many pattern question and time they give??

Deepak op

0

import java.util.Scanner; class Pattern6 { void print1(int n) { int l=n-2; for(int j=0;j<=n-2;j++) { for(int i=0;i