Een design engineer beoordeelt en verbetert een product onder meer op aspecten zoals veiligheid en functionaliteit. Verwacht als u op deze functie solliciteert dat u op bepaalde situaties gebaseerde en technische vragen moet beantwoorden. Zorg dat u bent voorbereid op een gesprek over uw ervaring met productontwerp, communicatie en aandacht voor details.
Tips om deze drie veelgestelde sollicitatievragen voor een design engineer te beantwoorden:
Zo antwoordt u: Een design engineer moet de vaardigheden hebben om te werken met bedrijfstakspecifieke software en apparaten. Laat de HR-manager zien dat u uitstekend op de hoogte bent van de technologie door te vertellen welke CAD- (Computer Aided Design) en CAE-software (Computer Aided Engineering) u gebruikt. Beschrijf daarnaast de technologieën die een belangrijke rol spelen in uw carrière als design engineer, bijvoorbeeld het MOSFET-circuitontwerp als u solliciteert op de functie van circuit design engineer.
Zo antwoordt u: Beantwoord deze vraag die betrekking heeft op persoonlijkheid, door aan te geven welke technieken u zou gebruiken om uw tijd te managen in deze situatie. U kunt het bijvoorbeeld hebben over het opstellen van tijdlijnen, het plannen en prioriteren van taken en het halen van deadlines.
Zo antwoordt u: De HR-manager stelt deze vraag om uw motivatie te beoordelen. Praat over de strategie die u gebruikt om gemotiveerd te blijven. Probeer een antwoord te geven dat gebaseerd is op uw ervaringen, zoals de zelfmotivatietechniek die u gebruikte toen u een parameter uit het ontwerpverzoek van het onderzoeks- en ontwikkelingsteam verkeerd begreep.
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@Rajiv : Your solution is completely wrong. It will fail for input of "aaa" Reason: on first check, you insert "a". On next check you remove it. On next check you again insert it and return that as your answer, even though it was repeated thrice. Minder
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program to find first non repeating character in a string c# - three ways
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My python implementation: def firstNonRepeatingCharacter(inputString): hashmap = {} for x in inputString: if (x in hashmap): hashmap[x] = hashmap[x] + 1 else: hashmap[x] = 1 for x in inputString: if (hashmap[x] > 1): continue else: return x return "No nonrepeating character found" Minder
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Hey, you should feel glad that you weren't accepted by them. This company is very cheap and doesn't treat its employees well. Minder
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I guess...but it is not the right way to interview candidates don't you think?
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That's really sad. They should rather go with Skype or any other means to interview. Now,. I have got an on-site call for Digital circuit design and I am giving it a serious thought 🤔 Minder
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It is a closed system as electricity is adding energy into the room. After a long time passes, the temperature increases as there's energy going in, but not leaving. Minder
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It's a closed system. Since the efficiency of heat transfer is not 100%, will generate heat and eventually heat up the room. Minder
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Since there is energy going into the room, it is open system without mass transfer. The room temperature will increase. Minder
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Without an enable bit on at least one of the mux's the maximum inputs would be 7. Minder
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I don't see it being possible with three standard 4-1 muxes... Using 4, this question is straight forward... The two selects of each mux are your 8 inputs... tie out put of each mux to the (11) case input to the mux. Minder
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We need 3 4:1 MUX and a And gate. Are we allowed to use 'and' gate?
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full adder can be got by 2 half adders and one OR gate; one half adder can be got by XOR, AND. Therefore, we need only OR, AND, XOR. All these three gates can be got by using MUX.? Minder
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Can be implemented using 8 Muxes.
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sum = a xor b xor cin carry = (a xor b) cin + ab You can easiy make XOR, OR AND, NOT using 2:1 mux. So 8 mux ?!? Minder
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Since they've clearly told sliding. Acceleration along the ramp is independent of the mass or the moment of Inertia. Hence, both reaches down at the same time. Minder
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Solid bar, smaller moment of inertia allows it to spin faster
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Solid reaches first
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"more the Ids, the lesser the drive strength is" This is exactly opposite of the actual fact...! Minder
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Use body effect, reverse biasing, this will reduce the drain current. another way can be change the gate input, according to the I-V characteristic Minder
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the first answer is definitely wrong, to decrease the driving capacity, please size down the ratio! Minder
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Your answer indicated the necessity of this question.
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The water level will decrease ( if the brick has a density greater than water, which of course a conventional brick does). When in the boat, the brick will displace a mass of water equal to it's own. So if it has a mass of 1kg it will displace 1kg of water. When thrown overboard it will now displace an amount of water equal to it's volume. As it sinks, it's density must be grater than water and therefore it's 1kg mass will take up a smaller volume than 1kg of water. Therefore the water level will decrease. As a styrofoam brick has a lower density than water it will not sink when thrown overboard. When floating it will displace a mass of water equal to that of the brick and therefore the water level will remain the unchanged. Minder
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A powerful tool in looking at questions like these intuitively rather than by the raw physics is to go to the extreme. Say the brick were of normal brick size but were made of some ultra-dense material...so dense that it would push an aircraft carrier down in the water to the brink of sinking. This would obviously cause the carrier to displace many thousands of gallons more water than it had been displacing before the brick was added. When the brick is thrown overboard, the carrier would come shooting up out of the water, now not displacing those additional thousands of gallons of water The volume of water displaced by the brick once it's in the water is comparatively insignificant. So clearly the water level will fall. Minder