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At bangalore Synechron is firing for external projects for their clients, sometimes even before client offer job to your profile Synechron will offer you job. So . Once after you joined Synechron you need to attend interview at client place, if you did not clear interview - then you lost it. and you don't have job. Synechron won't keep you in bench for much days !. be careful. I met few guys , they were resigned from other companies and joined Synechron. after joining Synechron they had to attend F2F interview with client . since they could not clear interviiew, they had to leave Synechron and they were jobless. So if you have EMIs running , then Synechron is not the right place :) Minder

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class Rtech { /* Return true if arr2[] is a subset of arr1[] */ static boolean isSubset(int arr1[], int arr2[], int m, int n) { int i = 0; int j = 0; for (i = 0; i < n; i++) { for (j = 0; j < m; j++) if (arr2[i] == arr1[j]) break; /* If the above inner loop was not broken at all then arr2[i] is not present in arr1[] */ if (j == m) return false; } /* If we reach here then all elements of arr2[] are present in arr1[] */ return true; } // Driver code public static void main(String args[]) { int arr1[] = { 11, 1, 13, 21, 3, 7 }; int arr2[] = { 11, 3, 7, 1 }; int m = arr1.length; int n = arr2.length; if (isSubset(arr1, arr2, m, n)) System.out.print("arr2[] is " + "subset of arr1[] "); else System.out.print("arr2[] is " + "not a subset of arr1[]"); } } Minder