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Swaz answer is almost correct however it does not work in all scenarios. lets assume: box 1 is labelled Oranges (O) box 2 is labelled Apples (A) box 3 is labelled Apples and Oranges (A+O) and that ALL THREE BOXES ARE LABELLED INCORRECTLY" Pick a fruit from box 1, 1) if you pick an Orange: - box 1's real label can only be O or A+O - box 1's current label is O - since ALL LABELS ARE INCORRECT then box 1's real label can not be O - box 1's new label should then be A+O by elimination - since ALL LABELS ARE INCORRECT - box 2's label is changed to O - box 3's label is changed to A - SOLVED 2) if you pick an Apple: - box 1's real label can only be A or A+O - box 1's current label is O - since ALL LABELS ARE INCORRECT then box 1's real label can not be O - this still leaves us with the choice between label A and label A+O - which would both be correct - FAILURE Solution: The trick is to actually pick a fruit from the A+O labeled box Pick a fruit from box 3: 1) if you pick an Orange: - box 3's real label can only be O or A - box 3's current label is A+O - since ALL LABELS ARE INCORRECT then box 3's real label can not be A+O - box 3's new label should then be O by elimination - since ALL LABELS ARE INCORRECT - box 1's label is changed to A - box 2's label is changed to A+O - SOLVED 2) if you pick an Apple: - box 3's real label can only be O or A - box 3's current label is A+O - since ALL LABELS ARE INCORRECT then box 3's real label can not be A+O - box 3's new label should then be A by elimination (not O) - since ALL LABELS ARE INCORRECT - box 1's label is changed to A+O - box 2's label is changed to O - SOLVED Minder
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It's easier to draw it out. There are only 2 possible combinations when all labels are tagged incorrectly. All you need to do is pick one fruit from the one marked "Apples + Oranges". If it's Apple, then change "Apple + Orange" to "Apple" The "Apple" one change to "Orange" The "Orange one change to "Apple + Orange" If it's Orange, then change "Apple + Orange" to "Orange" The "Apple" one change to "Apple + Orange" The "Orange" one change to ""Apple" Minder
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All the three boxes are names incorrectly. SO the bax lebeled Apples+Oranges contains only Oranges or Only Apples. Pick one fruit from it. If it is Orange then lebel the box as Orange. So the box lebeled Oranges contains Apples and the remaining contains both. Minder
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Maybe I'm having a bad day, but I don't get why F. is the answer.
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I believe it's E, not F. If A is true, B has to be true - contradiction. If B is true, D is also true - contradiction. If C is true, A and B have to be true, but they are not. D can't be true because we already ruled out all of those above D. (skip E) F can't be true because E would also be true, which contradicts F. (back to E) E may be true because we did rule out all of the above. And if E is true then F is false, which is also consistent. Minder
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This is incorrect. E only states that the letters above are incorrect, but does not disprove F. Thus, E also includes F as a true statement. However, F disproves the truth of E. Therefore the only answer does that is not contradicted by anything else is F. Minder
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Number the bottles 1-5. Collect a number of pills from each bottle corresponding to their bottle number. So, 1 pill from bottle 1, 2 from bottle 2, etc. If they all had 10 gram pills they should weigh 150 grams. The difference will be the number of the bottle the 9 gram pill came from. Example, bottle 3 has the 9 gram pills. Total weight read will be 147 grams. The difference of 3 is the bottle it came from. Minder
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Place all five bottles on the scale. It should say 49 grams on the scale. If you take out one bottle each time. Subtract the scale from before and after the bottle that has been taken off the scale. If it's 9. That's the bottle you're looking at. Minder
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What top poster said except you can label the bottles from 0 to 4 and save yourself a little work Minder
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One solution is to sort the array, then iterate through all neighboring pairs to find the pair with smallest difference. This is O(NlogN) solution. If the integers are bounded, you may be able to sort in O(N) time for an O(N) solution. Minder
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public static int[] find2Closest(int[] myArray) { assert(myArray.length >= 2): "myArray needs to be larger than 2"; Arrays.sort(myArray); //quickSort int indexMin1 = 0; int indexMin2 = 1; int min = myArray[indexMin1] - myArray[indexMin2]; for(int k = 0; k < myArray.length-1; k++) { int difference = Math.abs(myArray[k] - myArray[k+1]); if(difference < min) { min = difference; indexMin1 = k; indexMin2 = k+1; } } int[] values = new int[2]; values[0] = myArray[indexMin1]; values[1] = myArray[indexMin2]; return values; } Minder
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public class ClosestTwoNumber { public int[] findClosest2Number(int[] arr){ if(arr == null || arr.length diff) { min = diff; num1 = arr[i - 1]; num2 = arr[i]; } } if (num1 == -1 || num2 == -1) { throw new IllegalArgumentException(); } int[] result = new int[2]; result[0] = num1; result[1] = num2; return result; } Minder
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Contined...prior to lowering the bread into the toaster select the lowest heat setting. Once the bread is lowered set a timer to measure length of time before toast cycle completes and toasted bread pops up. Retest on all other heat settings and time each of these. Minder
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I would find a tester and I'd tell him/her to test the toaster by plugging it in. If the toaster doesn't toast the tester, it works; if it toasts the tester, it's broken. Minder
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He means "if you don't get electrocuted then the toaster works. If you die of electrocution then the toaster is broken" lol Minder
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public void (String input) { if (input == null || input.length == 0) return; for (int i = input.length-1; i >= 0; i--) { System.out.print(input.charAt(i)); } System.out.println(); } Minder
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public static void main(String [] args) { String a = "qwerty", rev = ""; //Scanner sc = new Scanner(System.in); //System.out.println("Enter the string : "); //String a = sc.nextLine(); for(int i = a.length()-1; i >= 0; i --) { rev = rev + a.charAt(i); } System.out.println(rev); } Minder
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myString[::-1]
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explained all phases of test lifecycle
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Software Testing Life Cycle 1.Requirment analysis 2.Test planning 3.Test Designing/Test case development 4.Environment setup 5.Test Execution 7.Test cycle closure/Test reporting Minder
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Software Testing Life Cycle 1.Requirment analysis 2.Test planning 3.Test Designing/Test case development 4.Environment setup 5.Test Execution 7.Test cycle closure/Test reporting Minder
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I like it.Hahaha
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because i cant get into google.
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Apple is quite known company, a lot of things I read or heard about it, but never experienced by myself. To work for Apple is a big honor and opportunity to develop my self. Also to exercise myself, what can I do to reach goals and just enjoy to work Minder
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mv
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mv filename1 filename2
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A9: cp filename1 filename2.
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I explained all the working and mechanism of my Final Year Project
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My final year project is game
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My BS final year project is Online Complaint management system and in MS my thesis is on Requirements Change Management Issues for E-Government in Pakistan. Minder