# 179

Sollicitatievragen voor User Experience Developer gedeeld door sollicitanten

## Meest gestelde sollicitatievragen

Sorteren: Relevantie|Populair|Datum
Er werd een Software Engineer, User Experience gevraagd...20 november 2016

### Given a linked list of characters, print the characters in reverse order.

3 antwoorden

reverse the linked list, iterate through it and print, reverse it back.

traverse through it using a recursive function with a printing statement after the traversal statement so when it gets to the end of the function and its returning, it will print along the way. Minder

def reverse[T](seq: Seq[T]): Seq[T] = { seq match { case Nil =&gt; Seq() case head :: tail =&gt; reverse(tail) :+ head } } println(reverse(List('A', 'B', 'C', 'D', 'E'))) Minder

### Using a nested for() loop is inefficient, can you do it more efficient than the native String.indexOf() method? Without nesting for loops or recursion.

2 antwoorden

Convert the strings to objects with each word being added as a property to speed up the lookup. I had heard of this technique but never done it myself. Minder

sort the words will be done in n Log n . for each word in 1st string do binary search on other string which will run in n log n so overall complexity will be n log n. Minder

### "You have 30 minutes to show us what you've got."

2 antwoorden

Ask more specifics on the position. The recruiter gave me NO information on the available position, so I was under the impression that I was up for consideration in several positions.. Minder

I can tell you what I don't got -- a job.

### Given two strings of words create an algorithm to return all the words that occur in only one of the two strings. A word can be in one string many times and still pass as long as it's not in the other.

2 antwoorden

My answer started out a simple string comparison, but then realized the algorithm needs to be a little more complex to satisfy the requirement. I turned the strings into arrays, then created a function that used a nested for loop to compare the arrays. similar to the native String.indexOf() method, only customized for the requirement. Minder

You can use a hash map to count the words in the two arrays. Words with count==1 are the answer Minder

### How to remove a text box out of 5 boxes arranged in loop (Parent Box to Child box) with the help of Javascript?

1 antwoorden

with the help of addClass and removeClass function using (this)

### how to make a bot for Candy crush

1 antwoorden

design an Algorithm using your common sense

1 antwoorden

Same thing happened to me - what company asks you to do a project - aka homework... stupid and a waste of time Minder

### Why did you want to join the company?

1 antwoorden

Benefits and my skills matches with the position

### Why should we choose you?

1 antwoorden

Because i'm more qualified for the job than most candidates waiting outside

Weergave: 1 - 10 van 179 sollicitatievragen

## Sollicitatievragen weergeven voor vergelijkbare functies

user experience designerweb graphic designersenior web developer.net developer

Glassdoor heeft 179 sollicitatievragen en verslagen van User experience developer sollicitaties. Bereid uw sollicitatiegesprek voor. Bedrijven ontdekken. Uw droombaan vinden.