Given an array with integers, return the array so that it will not have any consecutive duplicates.

Question

Anoniem · Accepted Answer

quickest answer is to run through array and do:
check value in hash
if not there then add it to hash and print
if it is there do nothing
O(n) in operation and memory

Anoniem · Answer

Previous does not fulfill the requirement for *consecutive*. Solution requires extra var:
void PrintArrayNoConsecutive(int[] array) {
 if (array.Length > 0) {
  var n = array[0];
  System.Println(n);
  for (int i = 1; i < array.Length; ++i) {
    if (n != array[i]) {
      n = array[i];
      System.Println(n); 
    }
  }
 }
}

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