Find the two largest numbers in an array

Question

David · Accepted Answer

def largest_2(arr)
  largest = nil
  largest2 = nil
  arr.each do |num|
    if largest == nil || num > largest
      largest2 = largest
      largest = num
    elsif largest2 == nil || num > largest2
      largest2 = num
    end
  end
  [largest, largest2]
end

Anoniem · Answer

public class TopTwo {

    public static void main(String args[]) {

        int[] arr = {3,6,4,1,5,2,10,20,30,25,29};

        int l1 = 0;
        int l2 = 0;

        l1 = l2 = arr[0];

        for (int i : arr) {
            if (i > l1) {
                l2 = l1;
                l1 = i;
            }
            if (i > l2 && i < l1) {
                l2 = i;
            }


        }

        System.out.println("l1 = " + l1 + ", l2 = " + l2);
    }
}

hivejin · Answer

int[] getLagestNumbers(int[] nums) {
        int first = Integer.MIN_VALUE;
        int second = Integer.MIN_VALUE;
        if (nums.length == 0 || nums.length  first) {
                second = first;
                first = nums[i];
            } else if (nums[i] > second) {
                second = nums[i];
            }
        }
        return new int[] { first, second };
    }

hivejin · Answer

int[] getLagestNumbers(int[] nums) {
        int first = Integer.MIN_VALUE;
        int second = Integer.MIN_VALUE;
        if (nums.length == 0 || nums.length  first) {
                second = first;
                first = nums[i];
            } else if (nums[i] > second) {
                second = nums[i];
            }
        }
        return new int[] { first, second };
    }

Anoniem · Answer

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