Java software engineer sollicitatievragen
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Sollicitatievragen voor Java Software Engineer gedeeld door sollicitantenMeest gestelde sollicitatievragen
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41 antwoorden↳
please let me know if anyone got Job
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36. If you get call then follow this interview experience
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How many of you waiting after 3rd round
Coding test: 1. Given a string, find out if there's repeat characters in it. 2. SQL. Given a Customer table and a Payment table (with Customer ID as primary and foreign key), write a query to output a list of customers who have not paid their bills in the last 3 months.
15 antwoorden↳
Did well on the first Java coding test. Solution using Hashset. Not so well on the SQL query. Able to give a query, but a few errors in it I am sure. Also there was a second questions regarding the SQL query, which we didn't have time to get to. So that was another bad thing. I am pretty sure I did not pass. But good learning experience. Minder
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import java.util.*; public class test { public static void main(String[] args) { String str = "abdc"; char[] arr = str.toCharArray(); HashSet set = new HashSet(); for (char i : arr ) { set.add(i); } if((set.size()) == (arr.length)) System.out.println("unique character"); else System.out.println("repetition"); } } Minder
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No
Write a program to print * * * * * * * * * * * * * * * * * * * * * * * * * * * * * with minimum number of variable use
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class StarPrint { public static void main (String[] args) throws java.lang.Exception { int i = 0, j = 0; for( i = 5; i > 0; i-- ){ for( j = 0; j < 5 - i; j++) System.out.print(" "); for( j = 0; j < i; j++ ) System.out.print("* "); System.out.println();} for( i = 3; i <= 6; i++ ){ for( j = 0; j <= 5 - i; j++) System.out.print(" "); for( j = 1; j < i; j++ ) System.out.print("* "); System.out.println(); } } } Minder
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public class Check { public static void main(String[] args) { int limit = 5; // Specify the number of lines as limit and check output int i=0,j=0; for(i=0;ilimit-i;j--)System.out.print(" "); for(j=limit;j>i;j--)System.out.print("* "); System.out.println(); } j=limit; for(;limit>1;limit--){ for(i=2;ilimit-2;i--)System.out.print("* "); System.out.println(); } } } Minder
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In the previous solution, the LESS THAN and GREATER THAN symbols have nit been parsed. public class Check { public static void main(String[] args) { int limit = 9; int i=0,j=0; for(i=0;i limit-i;j--)System.out.print(" "); for(j=limit;j > i;j--)System.out.print("* "); System.out.println(); } j=limit; for(;limit > 1;limit--){ for(i=2;i limit-2;i--)System.out.print("* "); System.out.println(); } } } Minder
Write a program for odd input the pattern output will as below n=1 *-* n=3 ***** *** *---* *** *****
12 antwoorden↳
import java.util.Scanner; public class Pattern{ public static void main(String[] args) { Scanner sc=new Scanner(System.in); int n=sc.nextInt(); for(int i=n;i>=2;i--){ for(int j=1;j<=2*n-(i-1);j++){ System.out.print(" "); } for(int k=1;k<=2*i-1;k++){ System.out.print("*"); } System.out.println(); } for(int i=1;i<=n-1;i++){ System.out.print(" "); } System.out.print("*"); for(int i=1;i<=n;i++){ System.out.print("-"); } System.out.print("*"); System.out.println(); for(int i=2;i<=n;i++){ for(int j=1;j<=n-i;j++){ System.out.print(" "); } for(int k=1;k<=2*i-1;k++){ System.out.print("*"); } System.out.println(); } } } Minder
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import java.util.Scanner; class New3 { public static void main(String ... args) { Scanner sc =new Scanner(System.in); int n=sc.nextInt(); for(int j=n,p=1;j>=2;j--,p++) { for(int i=1;i<=n+p;i++) System.out.print(" "); for(int k=1;k<=2*j-1;k++) System.out.print("*"); System.out.println(""); } for(int i=1;i<=n-1;i++) System.out.print(" "); System.out.print("*"); for(int i=1;i<=n;i++) System.out.print("-"); System.out.print("*"); System.out.println(""); int q=n-2; for(int j=2;j<=n;j++) { for(int i=1;i<=q;i++) System.out.print(" "); q--; for(int k=1;k<=2*j-1;k++) System.out.print("*"); System.out.println(""); } } } Minder
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import java.util.Scanner; public class webu { public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("enter the no"); int n=sc.nextInt(); for (int i = n; i >1; i--) { for(int j=1;j1){ for (int l =1 ; l <=2*i-1; l++) { System.out.print("*"); } System.out.println(" "); } } } } Minder
written test on basic java you can crack if you are average concept in java.
10 antwoorden↳
But what is the need of exam no result came 2 months have passed i suggest never go and waste your time. Minder
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you are right . I have never seen any interview experience that got job offer . at every end of year they have walkin drive . Thats look suspicious . At everytime when you go for interview they ask for reference. It might be true that they hire people who have strong refrence Minder
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Yes I got call. May be they call only those people who cracks Aptitude They may have high cut off. Minder
take input from user...3,5,7 etc and draw a pattern if input is 3 then *** *** * * *** * * * if input is 5 then ***** ***** * * * * * * ***** * * * * *
9 antwoorden↳
code for c language #include #include int main() {int n=7,i,j,l,k,m; for(i=1;i<=n;i++) printf("*"); printf(" "); for(i=1;i<=n;i++) printf("*"); printf("\n"); for(j=1;j<=n-2;j++) { for(k=1;k<=n-1;k++) printf(" "); printf("*"); printf(" "); printf("*"); printf("\n"); } for(i=1;i<=n-1;i++) printf(" "); for(i=1;i<=n;i++){ printf("*");} printf("\n"); for(i=1;i<=n;i++) { for(j=1;j<=n;j++) printf(" "); printf("*"); printf("\n"); } return 0; } Minder
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/* if input is 3 then *** *** * * *** * * * if input is 5 then ***** ***** * * * * * * ***** * * * * * */ import java.util.Scanner; public class Pattern3 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n=sc.nextInt(); for(int i=1; i<=2; i++){ for(int j=1; j<=n; j++){ System.out.print("*"); }System.out.print(" "); }System.out.println(); for(int i=1; i<=n-2; i++){ for(int j=1; j<=n-1; j++){ System.out.print(" "); }System.out.println("* *"); } for(int i=1; i<=(n+1)/2; i++){ System.out.print(" "); } for(int i=1; i<=n; i++){ System.out.print("*"); }System.out.println(); for(int i=1; i<=n; i++){ for(int j=1; j<=n; j++){ System.out.print(" "); }System.out.println("*"); } sc.close(); } } Minder
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check this import java.util.Scanner; public class MyClass { public static void main(String args[]) { Scanner sc =new Scanner(System.in); int n=sc.nextInt(); for(int i=0;i<2;i++){ for(int j=0;j Minder
If you add an element at a[1] position in arreylist and access a[2] element,what will happen?
9 antwoorden↳
Let arraylist contains {5,6,4,3,1} If you add 2 at 0th position then arraylist become {2,5,6,4,3,1} So according to question you will get old element of a[1] at a[2]'s position Minder
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We will get runtime exception:ArrayIndexOutOfBoundException
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Let arraylist contains {5,6,4,3,1} If you add 2 at 0th position then arraylist become {2,5,6,4,3,1} So according to question you will get old element of a[1] at a[2]'s position Minder
A company uses a format to exchange messages with us. You need to validate the input. The character encoding ASCII. Valid characters are between 0x20 (space) and 0x7E (~). write validate function to generate valid output or the error message.
9 antwoorden↳
public static void printValidMassage(){ String msg="204a6176617e"; String msg1=convertHextoChars(msg); boolean isValid=(msg1.startsWith(" ") && msg1.endsWith("~")) ? true : false; } private static String convertHextoChars(String hex) { StringBuffer sb = new StringBuffer(); for (int i=0; i Minder
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public static void printValidMassage(){ String msg="204a6176617e"; String msg1=convertHextoChars(msg); boolean isValid=(msg1.startsWith(" ") && msg1.endsWith("~")) ? true : false; System.out.println(isValid); } private static String convertHextoChars(String hex) { StringBuffer sb = new StringBuffer(); for (int i=0; i Minder
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for (int i=0; i
The first question was to print pattern that is n=1 *** n=3 * * *** *** ************ *** *** * * n=5 * * *** *** ***** ***** ******************* ***** ***** *** *** * *
9 antwoorden↳
I don't understand the logic of mid line.... import java.util.Scanner; /* 1 *** 3 * * *** *** ************ *** *** * * 5 * * *** *** ***** ***** ******************* ***** ***** *** *** * * */ public class Pattern1 { public static void main(String[] args) { Scanner sc =new Scanner(System.in); int n=sc.nextInt(); if(n>1){ for(int i=1; i1){ for(int i=(n+1)/2; i>=1; i--){ for(int j=1; j<=(((n+1))/2)+1-i; j++){ System.out.print(" "); } int k=0; while(k != (2*i)-1){ System.out.print("*"); k++; }k=0; System.out.print(" "); while(k!=(2*i-1)){ System.out.print("*"); k++; }k=0; System.out.println(); } } sc.close(); } } Minder
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import java.util.Scanner; /* 1 *** 3 * * *** *** ************ *** *** * * 5 * * *** *** ***** ***** ******************* ***** ***** *** *** * * */ public class Pattern1 { public static void main(String[] args) { Scanner sc =new Scanner(System.in); int n=sc.nextInt(); if(n>1){ for(int i=1; i1){ for(int i=(n+1)/2; i>=1; i--){ for(int j=1; j<=(((n+1))/2)+1-i; j++){ System.out.print(" "); } int k=0; while(k != (2*i)-1){ System.out.print("*"); k++; }k=0; System.out.print(" "); while(k!=(2*i-1)){ System.out.print("*"); k++; }k=0; System.out.println(); } } sc.close(); } } Minder
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package pattern; import java.util.Scanner; public class webu1 { public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("enter the no"); int n=sc.nextInt(); for(int i=1;i=1; i--) { for (int j = 0; j < n-i; j++) { System.out.print(" "); } for(int k=0;k<(2*i-1);k++){ System.out.print("*"); } System.out.print(" "); for(int k=0;k<(2*i-1);k++){ System.out.print("*"); } System.out.println(""); } } } Minder
How would you measure 4 litres of water if you have 3 litre and 5 litre canisters?
8 antwoorden↳
1) Pour water in 5 litre container 2) Pour 5 litre container into 3 litre until full. You are left with 2 litre in 5 litre container 3) Empty 3 liter container. Pour 2 litre into 3 litre container 4) Fill 5 litre container until full 5) Pour 1 litre into 3 litre container until full. Left with 4 litres in 5 litre container. Minder
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Add 2 full measures using the 5l, remove 2 full measures with the 3l, you are left with 4l. Minder
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Fill full water in the 5 litre canister, remove 3 liters of it to the 5 litre to the 3 litre canister. Keep remaining in the 5 litre canister(=2 litre) somwhere. Take another 5 litre water and perform the same procedure.= another 2 litre... 2+2 =4 litre.. done. Minder